Cambridge IGCSE Past Exam Papers

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Cambridge IGCSE past exam papers are now updated up to June 2025 examination series. Year 2028 Specimen papers are now available.

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Cambridge IGCSE is being offered by CAIE (Cambridge Assessment International Education) board from The University of Cambridge. These Cambridge IGCSE past exam papers are copyrighted by UCLES.

  • Updated up to June 2025 series past exam papers. YAY!
  • 2028 Specimen papers are now available.
  • “Specimen Papers” would be available when there is a change of syllabus for that year. Otherwise, “Specimen Papers” would not be available when the syllabus stays the same.
  • DO NOT download the past papers at last minute. We strongly suggest you to download everything you need at least 4 months before the exam.

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* If you are taking Edexcel iGCSE, please visit Edexcel iGCSE past exam papers page.


10,966 Replies to “Cambridge IGCSE Past Exam Papers”

  1. can any one help me solve this maths question.
    there are two similar cylinders. one cylinder has one liter and its diameter is 12 cm. the other cylinder has 440 ml and diameter is d. calculate d?

        • If they are similar then you could also use VSF and LSF

          VSF=Vsmall/Vbig=440/1000=11/25
          Cube root this answer. You get 0.7605904922.
          Now multiply this by 12 cm which should give you 9.127 cm.
          What is the answer do you know?

    • Similar cylinders means that the both volumes divided is equal to the cube of the divided diameters.
      1 litre= 1000 ml
      1000/440=(12/d)^3
      square root of 3(1000/440)= 12/d
      1.314767947=12/d
      1.314767947d=12
      d= 12/1.314767947
      d=9.13 cm

    • so 1000:440 (1 litre is 1000ml)
      then do the cube root
      so (cube root of 1000) : (cube root of 440)
      12 : x

      CROSS MULTIPLY THEEN, hope this helped

    • u use similar figures. so 12/1000 = d/440 and use simple algebra to get d… are u doing your igcse this year?? cuz this question is the basics so u shud be knowing…

    • the formula to find volume of similar objects is: new vol = old vol * k^3
      K is the scale factor, otherwise known as new length divided by old length.
      I took the 1 liter cylinder as the old one, and the 440 ml one as the new one.
      The info we know:
      old vol = 1 liter
      old diameter = 12cm
      new vol = 440 ml = 0.44 liters
      new diameter = d cm

      apply this to the formula:
      0.44 = 1 * (d/12)^3
      now you can change the subject
      0.44/1 = (d/12)^3
      cube root (0.44/1) = d/12
      (cube root (o.44/1)) * 12 = d
      d = 9.127 cm

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